Integrand size = 18, antiderivative size = 75 \[ \int (a+b x)^3 (A+B x) (d+e x) \, dx=\frac {(A b-a B) (b d-a e) (a+b x)^4}{4 b^3}+\frac {(b B d+A b e-2 a B e) (a+b x)^5}{5 b^3}+\frac {B e (a+b x)^6}{6 b^3} \]
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Time = 0.07 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {78} \[ \int (a+b x)^3 (A+B x) (d+e x) \, dx=\frac {(a+b x)^5 (-2 a B e+A b e+b B d)}{5 b^3}+\frac {(a+b x)^4 (A b-a B) (b d-a e)}{4 b^3}+\frac {B e (a+b x)^6}{6 b^3} \]
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Rule 78
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {(A b-a B) (b d-a e) (a+b x)^3}{b^2}+\frac {(b B d+A b e-2 a B e) (a+b x)^4}{b^2}+\frac {B e (a+b x)^5}{b^2}\right ) \, dx \\ & = \frac {(A b-a B) (b d-a e) (a+b x)^4}{4 b^3}+\frac {(b B d+A b e-2 a B e) (a+b x)^5}{5 b^3}+\frac {B e (a+b x)^6}{6 b^3} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.73 \[ \int (a+b x)^3 (A+B x) (d+e x) \, dx=a^3 A d x+\frac {1}{2} a^2 (3 A b d+a B d+a A e) x^2+\frac {1}{3} a (3 A b (b d+a e)+a B (3 b d+a e)) x^3+\frac {1}{4} b (3 a B (b d+a e)+A b (b d+3 a e)) x^4+\frac {1}{5} b^2 (b B d+A b e+3 a B e) x^5+\frac {1}{6} b^3 B e x^6 \]
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Leaf count of result is larger than twice the leaf count of optimal. \(141\) vs. \(2(69)=138\).
Time = 0.66 (sec) , antiderivative size = 142, normalized size of antiderivative = 1.89
method | result | size |
norman | \(\frac {b^{3} B e \,x^{6}}{6}+\left (\frac {1}{5} A \,b^{3} e +\frac {3}{5} B a \,b^{2} e +\frac {1}{5} b^{3} B d \right ) x^{5}+\left (\frac {3}{4} A a \,b^{2} e +\frac {1}{4} A \,b^{3} d +\frac {3}{4} B \,a^{2} b e +\frac {3}{4} B a \,b^{2} d \right ) x^{4}+\left (A \,a^{2} b e +A a \,b^{2} d +\frac {1}{3} B \,a^{3} e +B \,a^{2} b d \right ) x^{3}+\left (\frac {1}{2} a^{3} A e +\frac {3}{2} A \,a^{2} b d +\frac {1}{2} B \,a^{3} d \right ) x^{2}+a^{3} A d x\) | \(142\) |
default | \(\frac {b^{3} B e \,x^{6}}{6}+\frac {\left (\left (b^{3} A +3 a \,b^{2} B \right ) e +b^{3} B d \right ) x^{5}}{5}+\frac {\left (\left (3 a \,b^{2} A +3 a^{2} b B \right ) e +\left (b^{3} A +3 a \,b^{2} B \right ) d \right ) x^{4}}{4}+\frac {\left (\left (3 a^{2} b A +a^{3} B \right ) e +\left (3 a \,b^{2} A +3 a^{2} b B \right ) d \right ) x^{3}}{3}+\frac {\left (a^{3} A e +\left (3 a^{2} b A +a^{3} B \right ) d \right ) x^{2}}{2}+a^{3} A d x\) | \(149\) |
gosper | \(\frac {1}{6} b^{3} B e \,x^{6}+\frac {1}{5} x^{5} A \,b^{3} e +\frac {3}{5} x^{5} B a \,b^{2} e +\frac {1}{5} x^{5} b^{3} B d +\frac {3}{4} x^{4} A a \,b^{2} e +\frac {1}{4} x^{4} A \,b^{3} d +\frac {3}{4} x^{4} B \,a^{2} b e +\frac {3}{4} x^{4} B a \,b^{2} d +x^{3} A \,a^{2} b e +x^{3} A a \,b^{2} d +\frac {1}{3} x^{3} B \,a^{3} e +x^{3} B \,a^{2} b d +\frac {1}{2} x^{2} a^{3} A e +\frac {3}{2} x^{2} A \,a^{2} b d +\frac {1}{2} x^{2} B \,a^{3} d +a^{3} A d x\) | \(164\) |
risch | \(\frac {1}{6} b^{3} B e \,x^{6}+\frac {1}{5} x^{5} A \,b^{3} e +\frac {3}{5} x^{5} B a \,b^{2} e +\frac {1}{5} x^{5} b^{3} B d +\frac {3}{4} x^{4} A a \,b^{2} e +\frac {1}{4} x^{4} A \,b^{3} d +\frac {3}{4} x^{4} B \,a^{2} b e +\frac {3}{4} x^{4} B a \,b^{2} d +x^{3} A \,a^{2} b e +x^{3} A a \,b^{2} d +\frac {1}{3} x^{3} B \,a^{3} e +x^{3} B \,a^{2} b d +\frac {1}{2} x^{2} a^{3} A e +\frac {3}{2} x^{2} A \,a^{2} b d +\frac {1}{2} x^{2} B \,a^{3} d +a^{3} A d x\) | \(164\) |
parallelrisch | \(\frac {1}{6} b^{3} B e \,x^{6}+\frac {1}{5} x^{5} A \,b^{3} e +\frac {3}{5} x^{5} B a \,b^{2} e +\frac {1}{5} x^{5} b^{3} B d +\frac {3}{4} x^{4} A a \,b^{2} e +\frac {1}{4} x^{4} A \,b^{3} d +\frac {3}{4} x^{4} B \,a^{2} b e +\frac {3}{4} x^{4} B a \,b^{2} d +x^{3} A \,a^{2} b e +x^{3} A a \,b^{2} d +\frac {1}{3} x^{3} B \,a^{3} e +x^{3} B \,a^{2} b d +\frac {1}{2} x^{2} a^{3} A e +\frac {3}{2} x^{2} A \,a^{2} b d +\frac {1}{2} x^{2} B \,a^{3} d +a^{3} A d x\) | \(164\) |
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Leaf count of result is larger than twice the leaf count of optimal. 146 vs. \(2 (69) = 138\).
Time = 0.23 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.95 \[ \int (a+b x)^3 (A+B x) (d+e x) \, dx=\frac {1}{6} \, B b^{3} e x^{6} + A a^{3} d x + \frac {1}{5} \, {\left (B b^{3} d + {\left (3 \, B a b^{2} + A b^{3}\right )} e\right )} x^{5} + \frac {1}{4} \, {\left ({\left (3 \, B a b^{2} + A b^{3}\right )} d + 3 \, {\left (B a^{2} b + A a b^{2}\right )} e\right )} x^{4} + \frac {1}{3} \, {\left (3 \, {\left (B a^{2} b + A a b^{2}\right )} d + {\left (B a^{3} + 3 \, A a^{2} b\right )} e\right )} x^{3} + \frac {1}{2} \, {\left (A a^{3} e + {\left (B a^{3} + 3 \, A a^{2} b\right )} d\right )} x^{2} \]
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Leaf count of result is larger than twice the leaf count of optimal. 168 vs. \(2 (73) = 146\).
Time = 0.04 (sec) , antiderivative size = 168, normalized size of antiderivative = 2.24 \[ \int (a+b x)^3 (A+B x) (d+e x) \, dx=A a^{3} d x + \frac {B b^{3} e x^{6}}{6} + x^{5} \left (\frac {A b^{3} e}{5} + \frac {3 B a b^{2} e}{5} + \frac {B b^{3} d}{5}\right ) + x^{4} \cdot \left (\frac {3 A a b^{2} e}{4} + \frac {A b^{3} d}{4} + \frac {3 B a^{2} b e}{4} + \frac {3 B a b^{2} d}{4}\right ) + x^{3} \left (A a^{2} b e + A a b^{2} d + \frac {B a^{3} e}{3} + B a^{2} b d\right ) + x^{2} \left (\frac {A a^{3} e}{2} + \frac {3 A a^{2} b d}{2} + \frac {B a^{3} d}{2}\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 146 vs. \(2 (69) = 138\).
Time = 0.19 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.95 \[ \int (a+b x)^3 (A+B x) (d+e x) \, dx=\frac {1}{6} \, B b^{3} e x^{6} + A a^{3} d x + \frac {1}{5} \, {\left (B b^{3} d + {\left (3 \, B a b^{2} + A b^{3}\right )} e\right )} x^{5} + \frac {1}{4} \, {\left ({\left (3 \, B a b^{2} + A b^{3}\right )} d + 3 \, {\left (B a^{2} b + A a b^{2}\right )} e\right )} x^{4} + \frac {1}{3} \, {\left (3 \, {\left (B a^{2} b + A a b^{2}\right )} d + {\left (B a^{3} + 3 \, A a^{2} b\right )} e\right )} x^{3} + \frac {1}{2} \, {\left (A a^{3} e + {\left (B a^{3} + 3 \, A a^{2} b\right )} d\right )} x^{2} \]
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Leaf count of result is larger than twice the leaf count of optimal. 163 vs. \(2 (69) = 138\).
Time = 0.28 (sec) , antiderivative size = 163, normalized size of antiderivative = 2.17 \[ \int (a+b x)^3 (A+B x) (d+e x) \, dx=\frac {1}{6} \, B b^{3} e x^{6} + \frac {1}{5} \, B b^{3} d x^{5} + \frac {3}{5} \, B a b^{2} e x^{5} + \frac {1}{5} \, A b^{3} e x^{5} + \frac {3}{4} \, B a b^{2} d x^{4} + \frac {1}{4} \, A b^{3} d x^{4} + \frac {3}{4} \, B a^{2} b e x^{4} + \frac {3}{4} \, A a b^{2} e x^{4} + B a^{2} b d x^{3} + A a b^{2} d x^{3} + \frac {1}{3} \, B a^{3} e x^{3} + A a^{2} b e x^{3} + \frac {1}{2} \, B a^{3} d x^{2} + \frac {3}{2} \, A a^{2} b d x^{2} + \frac {1}{2} \, A a^{3} e x^{2} + A a^{3} d x \]
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Time = 0.07 (sec) , antiderivative size = 141, normalized size of antiderivative = 1.88 \[ \int (a+b x)^3 (A+B x) (d+e x) \, dx=x^2\,\left (\frac {A\,a^3\,e}{2}+\frac {B\,a^3\,d}{2}+\frac {3\,A\,a^2\,b\,d}{2}\right )+x^5\,\left (\frac {A\,b^3\,e}{5}+\frac {B\,b^3\,d}{5}+\frac {3\,B\,a\,b^2\,e}{5}\right )+x^3\,\left (\frac {B\,a^3\,e}{3}+A\,a\,b^2\,d+A\,a^2\,b\,e+B\,a^2\,b\,d\right )+x^4\,\left (\frac {A\,b^3\,d}{4}+\frac {3\,A\,a\,b^2\,e}{4}+\frac {3\,B\,a\,b^2\,d}{4}+\frac {3\,B\,a^2\,b\,e}{4}\right )+A\,a^3\,d\,x+\frac {B\,b^3\,e\,x^6}{6} \]
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